Question 22 • Probability and Statistics with Applications Honors Sem-2-FL-1210300 (2024-2025)
There are 13 diamonds and 39 non-diamonds. The probability of exactly three diamonds among four cards is (13 choose 3)(39 choose 1) divided by (52 choose 4), which is 11,154 ÷ 270,725 ≈ 0.041, or about 4%. So the correct choice is 4%.
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