Let r = ⟨5, –1⟩, s = ⟨6, 0⟩, and t = ⟨–1, –3⟩. Aaron incorrectly determined 2r + 4s – 7t as ⟨41, –23⟩. Review his calculations.2r + 4s – 7t2⟨5, –1⟩ + 4⟨6, 0⟩ – 7⟨–1, –3⟩⟨10, –2⟩ + ⟨24, 0⟩ + ⟨7, –21⟩⟨41, –23⟩

Multiplying t = ⟨–1, –3⟩ by –7 gives –7t = ⟨7, 21⟩, because –7 times –3 is positive 21. Aaron wrote ⟨7, –21⟩, so he did not correctly distribute the negative when subtracting 7t. The correct sum is ⟨10, –2⟩ + ⟨24, 0⟩ + ⟨7, 21⟩ = ⟨41, 19⟩.

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