What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the horizontal?

Only the horizontal component of the pulling force accelerates the wagon along the ground. That component is 44 cos(35°) ≈ 36.0 N, so the acceleration is 36.0 N ÷ 10 kg = 3.60 m/s². The correct choice is 3.60 m/s².

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