A student determines that she used 0.0665 mol of sodium hydroxide (NaOH) to completely titrate 25.00 mL of sulfuric acid solution (H2SO4). What is the molarity of the sulfuric acid?

The balanced reaction is H2SO4 + 2 NaOH → Na2SO4 + 2 H2O, so 2 mol of NaOH react with 1 mol of H2SO4. The acid amount is 0.0665 ÷ 2 = 0.03325 mol. Convert 25.00 mL to 0.02500 L, then calculate molarity: 0.03325 ÷ 0.02500 = 1.33 M. The sulfuric acid molarity is 1.33 M, choice C.

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