Find the 6th term of the expansion of (2p - 3q)11.

The 6th term uses the 5th power of the second term: \(\binom{11}{5}(2p)^6(-3q)^5\). This equals \(462\cdot64\cdot(-243)p^6q^5=-7{,}185{,}024p^6q^5\). So the answer is choice B, \(-7{,}185{,}024p^6q^5\).

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