Question 5 • GA-Advanced Algebra: Concepts and Connections CR
With 7 buses, if all were small, they would hold 7 × 45 = 315 students. Each large bus adds 15 seats, so at least 3 buses must be large to reach 360 students. Using 3 large buses and 4 small buses holds 3 × 60 + 4 × 45 = 360 students and costs 3 × $300 + 4 × $200 = $1,700. Six buses can hold 360 only if all are large, which costs $1,800, so the minimum is $1,700, choice C.
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