A series circuit contains three 2 Ω resistors and a 6 Ω resistor. The current in each resistor is 4.0 A.

In a series circuit, the total resistance is the sum of the resistors: 2 Ω + 2 Ω + 2 Ω + 6 Ω = 12 Ω. Using Ohm’s law, V = IR = 4.0 A × 12 Ω = 48 V, so the correct choice is 48 V.

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