For a standard normal distribution, find the approximate value of P(−0.78≤z≤1.16). Use the portion of the standard normal table to help answer the question. z Probability 0 point 0 0 0 point 5 0 0 0 0 point 1 6 0 point 5 6 3 6 0 point 2 2 0 point 5 8 7 1 0 point 7 8 0 point 7 8 2 3 1 point 0 0 0 point 8 4 1 3 1 point 1 6 0 point 8 7 7 0 1 point 7 8 0 point 9 6 2 5 2 point 0 0 0 point 9 7 7 2
The table gives Φ(1.16) ≈ 0.8770 and Φ(0.78) ≈ 0.7823. By symmetry, Φ(−0.78) = 1 − 0.7823 = 0.2177. So P(−0.78 ≤ z ≤ 1.16) ≈ 0.8770 − 0.2177 = 0.6593, or about 66 percent. The correct choice is C, 66 percent.
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