Shelia is dividing x4 – 4x3 + 4x2 – 6x + 5 by x – 1 using a division table. QuotientDivisor x3– 3x2+ x– 5xx4–3x3x2A– 1–x33x2BCWhat are the missing values in the table?

Multiply each term of the quotient by each term of the divisor. The quotient term −5 multiplied by x gives A = −5x, and the quotient term x multiplied by −1 gives B = −x; then −5 multiplied by −1 gives C = 5. These products fill the missing table entries.

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