A force of 10 newtons acts in a direction 75° above horizontal, moving an object 15 meters from (0, 0) to (15, 0). What is the work done by the force?

Work is the force component in the direction of motion multiplied by the displacement: W = Fd cos θ. The displacement is 15 m horizontally, while the 10 N force is 75° above horizontal, so W = 10 × 15 × cos 75° ≈ 38.82 J. Therefore, the correct choice is 38.82 joules.

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