Question 10 • Physics
For a point source charge, the electric field is E = k|q|/r², so |q| = Er²/k. Substituting E = 1236 N/C, r = 4 m, and k = 8.99 × 10⁹ N·m²/C² gives |q| = (1236 × 4²)/(8.99 × 10⁹) ≈ 2.2 × 10⁻⁶ C. Since 10⁻⁶ C is one microcoulomb, the charge is 2.2 μC, choice A.
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