A point charge of 8 point 0 µC is placed 0 point 0 5 0 m from a rod that has an electric field of 1 point 5 times 10 cubed cap n over cap c What is the electric potential energy of the point charge?

For a uniform electric field, the potential difference over 0.050 m is ΔV = Ed = (1.5 × 10³ N/C)(0.050 m) = 75 V. The charge’s electric potential energy is U = qΔV = (8.0 × 10⁻⁶ C)(75 V) = 6.0 × 10⁻⁴ J, so the answer is choice C, 6.0 × 10⁻⁴ J.

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