The electric field between two parallel plates has a magnitude of 875 cap n over cap c The positive plate is 0 point 0 0 2 m away from the negative plate. What is the electric potential difference between the plates?

For a uniform electric field between parallel plates, the potential difference in magnitude is ΔV = Ed. Using E = 875 N/C and d = 0.002 m gives ΔV = 875 × 0.002 = 1.75 V, which rounds to 1.8 × 10⁰ V. Therefore, the correct choice is 1.8 × 10⁰ V.

AI-written and checked against the verified answer.