A series circuit contains three 2 Ω resistors and a 6 Ω resistor. The current in each resistor is 4.0 A. What is the voltage of the battery in the circuit?
Answer
A
2 point 0 cap v
B
32 cap v
C
3 point 0 cap v
D
48 cap v
Explanation
In a series circuit, resistances add: 2 Ω + 2 Ω + 2 Ω + 6 Ω = 12 Ω. Using Ohm’s law, V = IR = (4.0 A)(12 Ω) = 48 V. The battery voltage is 48 V, choice D.
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