A coffee maker has a power rating of 850 point 0 cap w and a resistance of 18 point 4 cap omega What is the current in the coffee maker?

Use the power relationship P = I²R, so the current is I = √(P/R). Substituting the values gives I = √(850.0 W ÷ 18.4 Ω) ≈ √46.2 ≈ 6.80 A. Therefore, the current is 6.80 A, choice A.

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