The molar heat of fusion for water is 6 point 0 1 kJ over mol How much energy must be added to a 75 point 0 - g block of ice at 0 times degree C to change it to 75 point 0 g of liquid water at 0 times degree C ? Use q is equal to n triangle cap h

Use the molar mass of water, about 18.0 g/mol, to find the amount of water: 75.0 g ÷ 18.0 g/mol = 4.17 mol. Then calculate the energy for melting: q = nΔH₍fus₎ = 4.17 mol × 6.01 kJ/mol ≈ 25.0 kJ. The correct choice is D, 25.0 kJ.

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