What is the center of a circle whose equation is x squared plus y squared minus 12 x minus 2 y plus 12 is equal to 0 ?

For a circle in standard form, the center is (h, k) in (x − h)² + (y − k)² = r². Completing the square gives (x − 6)² + (y − 1)² = 25, so the center is (6, 1). This matches choice A, 6 comma 1.

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