What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0?

For a circle in the form x² + y² + Dx + Ey + F = 0, the center is (−D/2, −E/2). Here D = −12 and E = −2, so the center is (6, 1), which is choice C.

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