7
QuizMultiple Choice

Equations in One Variable

Question 7 • LA-Algebra II A

A school spent $150 on advertising for a breakfast fundraiser. Each plate of food was sold for $8.00 but cost the school $2.00 to prepare. After all expenses were paid, the school raised $2,400 at the fundraiser. Which equation can be used to find x, the number of plates that were sold?

Answer
A
6x – 150 = 2,400
B
6x + 150 = 2,400
C
10x – 150 = 2,400
D
10x + 150 = 2,400

Explanation

Each plate brings in $8.00, and preparing it costs $2.00, so the profit per plate is $8 − $2 = $6. The school also spent $150 on advertising, so its net fundraiser proceeds are 6x − 150. Setting that equal to the $2,400 raised gives 6x − 150 = 2,400, which is choice A.

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