Question 7 • Precalculus
The foci have midpoint (7, 0), so the center is (7, 0), and the hyperbola opens vertically because the foci differ in their y-coordinates. For a vertical hyperbola, the directrix is y = k + a²/c; here 16/5 = a²/5, so a² = 16. Since c² = a² + b² and c = 5, b² = 25 − 16 = 9. Thus the equation is y²/16 − (x − 7)²/9 = 1, which is choice A.
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