What is the equation of the line that is perpendicular to the line y is equal to 3 fifths x plus 10 and passes through the point 15 comma negative 5 ?

The given line has slope 3/5, so a perpendicular line has slope −5/3, the negative reciprocal. Using the point (15, −5) in y = mx + b gives −5 = (−5/3)(15) + b = −25 + b, so b = 20. The equation is y = −5/3x + 20, which is choice C.

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