AnswersPA-Geometry B-CRReciprocal Trigonometric Functions

Evaluating the Six Trigonometric Functions Answers

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1
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Which statement(s) are true based on the Pythagorean identities?

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
E
Option
Option E
2
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What is

Question illustration
A
–12/13
B
–5/13
C
5/13
D
12/13
3

Which identity can you now use to find cos(t)?

A
cos(t) = 1 / sec(t)
B
cot(t) = 1 / tan(t)
C
tan(t) = sin(t) / cos(t)
4

What is cos(t)?

A
Option
Option A
B
Option
Option B
C
Option
Option C
5

-8/17-15/178/17✔ 17/8

A
-8/17
B
-15/17
C
8/17
D
✔ 17/8
6

-15/8-15/17✔ -8/158/17

A
-15/8
B
-15/17
C
✔ -8/15
D
8/17
7

Which identity would be best to start with?

A
sin²(t) + cos²(t) = 1
B
tan²(t) + 1 = sec²(t)
C
1 + cot²(t) = csc²(t)
8

What is

Question illustration
A
–12/13
B
–5/13
C
5/13
D
12/13
9

Which statement(s) are true based on the Pythagorean identities?

A
Option
B
Option
C
Option
D
Option
E
Option
10

Which identity would be best to start with?

A
sin²(t) + cos²(t) = 1
B
tan²(t) + 1 = sec²(t)
C
1 + cot²(t) = csc²(t)
11

What is sec(t)?

A
Option
Option A
B
Option
Option B
C
Option
Option C
12

What is cos(t)?

A
Option
B
Option
C
Option
13

Use the diagram shown to answer the questions.If you dropped a vertical line from P to the x-axis to make a right triangle, what is the length of the hypotenuse, r? ⇒ 13

Answer:

13

14

Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

Answers:
sin(θ) =:-15/17
cos(θ) =:8/17
tan(θ) =:-15/8
csc(θ) =:-17/15
sec(θ) =:17/8
cot(θ) =:-8/15
15

Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

Answers:
sin(θ) =:-15/17
cos(θ) =:8/17
tan(θ) =:-15/8
csc(θ) =:-17/15
sec(θ) =:17/8
cot(θ) =:-8/15
16

What is sec(t)?

A
Option
Option A
B
Option
Option B
C
Option
Option C
17

-15/8-15/17✔ 8/178

A
-15/8
B
-15/17
C
✔ 8/17
D
8
18

Which identity can you now use to find cos(t)?

A
cos(t) = 1 / sec(t)
B
cot(t) = 1 / tan(t)
C
tan(t) = sin(t) / cos(t)
19

✔ -15/8-15/178/17-8/15

A
✔ -15/8
B
-15/17
C
8/17
D
-8/15
20

-15/17✔ -17/1517/15-17/8

A
-15/17
B
✔ -17/15
C
17/15
D
-17/8

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