AnswersGA-Advanced Algebra Concepts and Connections CREvaluating the Six Trigonometric Functions

Evaluating the Six Trigonometric Functions Answers

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-15/8-15/178/178

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-15/8
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-15/17
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8/17
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8
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-15/8-15/178/17-8/15

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-15/17-17/1517/15-17/8

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-8/17-15/178/1717/8

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-8/17
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-15/8-15/17-8/158/17

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-15/8
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-15/8-15/178/17-15

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-15/8
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8/17
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-15
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Which value(s) are incorrect?

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Option
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Option
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cosine (theta) = StartFraction StartRoot 2 EndRoot Over 2 EndFraction , and StartFraction 3 pi Over 2 EndFraction less-than theta less-than 2 pi, evaluation sine (theta) and tangent (theta)

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10

Use the identity sin²(A) + cos²(A) = 1tan²(A) + 1 = sec²(A)1 + cot²(A) = csc²(A)

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sin²(A) + cos²(A) = 1
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tan²(A) + 1 = sec²(A)
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1 + cot²(A) = csc²(A)
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Negative StartFraction 2 StartRoot 2 EndRoot Over 3 EndFraction

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Negative StartFraction 2 StartRoot 2 EndRoot Over 3 EndFraction
Option A
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Negative four-thirds
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Four-thirds
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StartFraction 2 StartRoot 2 EndRoot Over 3 EndFraction
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-15/8✔ -15/178/17-15

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-15
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Question text not available

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Question text not available

Answer:

To find the values of the six trigonometric functions for the angle θ with the terminal side passing through (5, –2), first identify the coordinates x = 5 and y = –2. Since the x-coordinate is positive and the y-coordinate is negative, the point is in Quadrant IV. Next, calculate the radius (r) using the Pythagorean theorem: r = √(5² + (–2)²) = √(25 + 4) = √29. Then apply the trigonometric definitions: sin(θ) = y/r = –2/√29 = –2√29/29 cos(θ) = x/r = 5/√29 = 5√29/29 tan(θ) = y/x = –2/5 csc(θ) = r/y = –√29/2 sec(θ) = r/x = √29/5 cot(θ) = x/y = –5/2

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Which value(s) are incorrect?

A
Option
Option A
B
Option
Option B
C
Option
Option C
D
Option
Option D
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Option
Option E
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Option
Option F
19

Use the identity sin²(A) + cos²(A) = 1✔ tan²(A) + 1 = sec²(A)1 + cot²(A) = csc²(A)

A
sin²(A) + cos²(A) = 1
B
✔ tan²(A) + 1 = sec²(A)
C
1 + cot²(A) = csc²(A)

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