Exponential and Logarithmic Functions — Test

Question 11 • Algebra II

Which graph shows the solution to the equation? the log base 3 of x is equal to the log base 0 point 5 of x

Answer

Image with description On a coordinate plane the x axis lists from negative 5 to 5 by 1 and y axis lists from negative 5 to 5 by 1. There are two hyperbolas defined for positive values of x. One of the parabola has vertex (3 comma 0) and it approaches the x axis and the line x equals 1. The other hyperbola has vertex at (2 comma negative 1) and it approaches the x axis and the line x equals 1.

Image with description On a coordinate plane the x axis lists from negative 5 to 5 by 1 and y axis lists from negative 5 to 5 by 1. There is a curved graph that passes through (negative 4 comma negative 2), and (negative 2 comma negative 1). It increases in the third quadrant, changes direction at the origin, and then again increases in the first quadrant passing through (5 comma 1 point 5). There is line that passes through the origin, (1 comma 1), and (2 comma 2).

Image with description On a coordinate plane the x axis lists from negative 5 to 5 by 1 and y axis lists from negative 5 to 5 by 1. Two curves are drawn. One of the curve approaches the y axis in the first quadrant and passes through (2 comma negative 1) and (4 comma negative 2). The other curve passes through (3 comma 1), (1 comma 0), and approaches y axis in the fourth quadrant.

Image with description On a coordinate plane the x axis lists from negative 5 to 5 by 1 and y axis lists from negative 5 to 5 by 1. There is a smooth curve that passes through (0 point 5 comma negative 1), and (1 comma 0), and approaches y axis in the fourth quadrant. There is a line that passes through the origin, (1 comma 1), and (2 comma 2).

Explanation

The two logarithmic expressions are equal where their graphs intersect. Both have value 0 at x = 1, since log base 3 of 1 and log base 0.5 of 1 are both 0. The graph of log base 3 of x increases through (3, 1), while log base 0.5 of x decreases through (2, −1) and (4, −2); choice C shows both curves.

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