What is the true solution to the given equation? 2 log sub 3 6 x minus log sub 3 of 4 x is equal to 2 log sub 3 open paren x plus 2 close paren

The logarithms require x > 0. Using log rules, the left side becomes log₃((6x)²/(4x)) = log₃(9x), and the right side is log₃((x + 2)²). Since the logarithms have the same base, set their arguments equal: 9x = (x + 2)². This gives x² − 5x + 4 = 0, so x = 1 or x = 4; both satisfy the domain, matching “x is equal to 1 and x is equal to 4.”

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