Factoring Polynomials Completely Answers

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1
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Check all of the possible first steps in factoring a polynomial with four terms.

A
factor out a GCF
B
factor the difference of cubes
C
factor a sum of cubes
D
factor a difference of squares
E
factor a perfect-square trinomial
F
factor by grouping
2
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A polynomial has two terms. Check all of the factoring methods that should be considered.

A
common factor
B
difference of cubes
C
sum of cubes
D
difference of squares
E
perfect-square trinomial
F
factoring by grouping
3

Which polynomials are prime? Check all of the boxes that apply.

A
x2 + 9
B
x2 – 9
C
x2 + 3x + 9
D
–2x2 + 8
5

Which expression does not factor?

A
m3 + 1
B
m3 – 1
C
m2 + 1
D
m2 – 1
6

What is the completely factored form of 25x4 – 16y2?

A
(5x4 + 4y)(5x – 4y)
B
(5x3 + 4y)(5x2 – 4y)
C
(5x2 + 4y)(5x2 – 4y)
D
25x4 – 16y2
7

What is the completely factored form of 2x2 – 32?

A
(2x2 + 16)(x – 16)
B
2(x + 4)(x – 4)
C
2(x + 8)(x – 4)
D
2(x – 8)(x – 4)
8

What is the completely factored form of x4y – 4x2y – 5y?

A
y(x2 – 5)(x2 + 1)
B
y(x2 + 5)(x2 – 1)
C
(x2y – 5)(x2 + 1)
D
(x2y + 5)(x2 – 1)
9

Which of the following statements about 42xy – 49x + 30y – 35 are true? Check all of the boxes that apply.

A
One of the factors is (6y + 7).
B
One of the factors is (7x + 5).
C
One of the factors is (6y – 7).
D
One of the factors is (7x – 5).
E
This expression is prime.
10

The expression is equivalent and is completely factored.The expression is equivalent, but the (a2 – 4) term is not completely factored.The expression is equivalent, but the (a4 + 4a2 + 16) term is not completely factored.The expression is not equivalent.

A
The expression is equivalent and is completely factored.
B
The expression is equivalent, but the (a2 – 4) term is not completely factored.
C
The expression is equivalent, but the (a4 + 4a2 + 16) term is not completely factored.
D
The expression is not equivalent.
11

Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.

Answer:

First check for a greatest common factor. Then factor by grouping: x^2(2x + 5) - 4(2x + 5) = (2x + 5)(x^2 - 4). Recognize x^2 - 4 as a difference of squares and factor completely: (2x + 5)(x + 2)(x - 2).

12

Which important information did you include in your description? Check all of the boxes that apply.

A
Check for a greatest common factor.
B
There are four terms, so consider factoring by grouping, which yields (2x +5)(x2 – 4).
C
Identify x2 – 4 as the difference of squares.
D
Factor completely as (2x + 5)(x + 2)(x – 2).

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