AnswersCommon Core Algebra I B-ICFactoring Polynomials: GCF

Factoring Polynomials: GCF Answers

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What did you include in your response? Check all that apply.

A
1 is the GCF of the coefficients.
B
There are no common variables among all three terms of the polynomial.
C
5b4 is the GCF of –25a2b5 and –35b4, but not a3.
D
a2 is a factor of a3 and – 25a2b5, but not –35b4.
3

What is the GCF of 44j5k4 and 121j2k6?

A
4j3k2
B
4j2k4
C
11j3k2
D
11j2k4
5

What is the factored form of the polynomial 27x2y – 43xy2?

A
xy(27x – 43y)
B
x2y2(27 – 43)
C
3xy(9x – 17y)
D
3x2y(9 – 14y)
6

Which statements are true about the polynomial 28vw + 49v + 35w? Check all that apply.The coefficients have no common factors other than 1.There are no common variables among all three terms.The GCF of the polynomial is 7v.Each term written as the product, where one factor is the GCF, is 7(28vw) + 7(49v) + 35(w).The resulting expression when factoring out the GCF is 7(4vw + 7v + 5w).

A
The coefficients have no common factors other than 1.
B
There are no common variables among all three terms.
C
The GCF of the polynomial is 7v.
D
Each term written as the product, where one factor is the GCF, is 7(28vw) + 7(49v) + 35(w).
E
The resulting expression when factoring out the GCF is 7(4vw + 7v + 5w).
8

Factor 26r3s + 52r5 – 39r2s4. What is the resulting expression?

A
13(2r3s + 4r5 – 3r2s4)
B
13r2s(2r + 4r3 – 3s3)
C
13r2(2rs + 4r3 – 3s4)
D
13r2(26r3s + 52r5 – 39r2s4)
9

Which statements are true about David’s work? Check all that apply.

A
The GCF of the coefficients is correct.
B
The GCF of the variable b should be b4 instead of b2.
C
The variable c is not common to all terms, so a power of c should not have been factored out.
D
The expression in step 5 is equivalent to the given polynomial.
E
In step 6, David applied the distributive property.

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Factoring Polynomials: GCF Answers — Common Core…