Question 9 • Algebra II
For a monomial to be a perfect cube, each variable’s exponent must be divisible by 3, and the coefficient must also be a perfect cube. The exponents 18, 3, and 21 are all divisible by 3, but 215 is not a perfect cube. So the number that needs to be changed is 215, choice B.
AI-written and checked against the verified answer.