What is the factorization of 216x12 – 64?

Recognize 216x^12 − 64 as a difference of cubes: 216x^12 = (6x^4)^3 and 64 = 4^3. Apply a^3 − b^3 = (a − b)(a^2 + ab + b^2), using a = 6x^4 and b = 4. This gives (6x^4 − 4)(36x^8 + 24x^4 + 16), which is choice C.

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