The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k?

Recognize 8x³ − 125 as a difference of cubes: (2x)³ − 5³. Using a³ − b³ = (a − b)(a² + ab + b²), the second factor is 4x² + 10x + 25, so j = 4 and k = 10.

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