Question 6 • Precalculus
For values of x near −1 (but not equal to −1), use the rule f(x) = x² − ⅓x. Substituting −1 into this polynomial gives (−1)² − ⅓(−1) = 1 + ⅓ = 4/3, so the limit is 4/3, choice D. The separately defined value f(−1) = −1 does not affect the limit.
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