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Function Operations

Question 6 • FL-1200330-Algebra 2 Sem 1 - Flex

r(x) = –x² + 3x s(x) = 2x + 1(s – r)(x) = –x² + 3x – 2x + 1X (–x² + 3x) – (2x + 1)✔ (2x + 1) – (–x² + 3x)2x + 1 – x² + 3x

Answer
A
–x² + 3x – 2x + 1
B
X (–x² + 3x) – (2x + 1)
C
✔ (2x + 1) – (–x² + 3x)
D
2x + 1 – x² + 3x
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