Question 3 • Precalculus
For y = log₄(x + 3), the logarithm’s input must be positive, so the graph has a vertical asymptote at x = −3. Setting y = 0 gives x + 3 = 1, so the graph passes through (−2, 0); setting y = 1 gives x + 3 = 4, so it passes through (1, 1). These features match choice A.
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