Question 9 • Algebra II
Because the polynomial has rational coefficients and √5 is a root, its conjugate −√5 must also be a root. Together with the root 2, the lowest-degree polynomial is 3(x − √5)(x + √5)(x − 2), where 3 gives the required leading coefficient. Expanding gives 3(x² − 5)(x − 2) = 3x³ − 6x² − 15x + 30, which is choice C.
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