A balloon that had a volume of 3 point 5 0 liters at 25 point 0 times degree C is placed in a hot room at 40 point 0 times degree C If the pressure remains constant at 1 point 0 0 atm, what is the new volume of the balloon in the hot room? Use the fraction with numerator cap v sub 1 and denominator cap t sub 1 is equal to the fraction with numerator cap v sub 2 and denominator cap t sub 2
At constant pressure, Charles’s law relates volume to temperature in kelvins: V₁/T₁ = V₂/T₂. Convert the temperatures: 25.0°C = 298.15 K and 40.0°C = 313.15 K. Then V₂ = 3.50 L × (313.15 K ÷ 298.15 K) ≈ 3.68 L, so the correct choice is 3.68 liters.
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