Consider the reaction. cap n sub 2 times g plus 3 cap h sub 2 g rightarrow 2 NH sub 3 g How many grams of cap n sub 2 are required to produce 100 point 0 liters of NH sub 3 at STP?

At STP, 1 mole of gas occupies 22.4 L, so 100.0 L of NH₃ is 100.0 ÷ 22.4 = 4.46 mol NH₃. From N₂ + 3H₂ → 2NH₃, 1 mol N₂ produces 2 mol NH₃, so 4.46 mol NH₃ requires 2.23 mol N₂. Multiplying by N₂’s molar mass, 28.0 g/mol, gives about 62.5 g, choice C.

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