Question 2 • Chemistry
First convert potassium chlorate to moles: 10.0 g ÷ 122.55 g/mol = 0.0816 mol KClO₃. The balanced equation shows that 2 mol KClO₃ produce 3 mol O₂, so this makes 0.0816 × 3/2 = 0.122 mol O₂. At STP, 1 mol of gas occupies 22.4 L, giving 0.122 × 22.4 = 2.74 L. The answer is 2.74 liters of oxygen.
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