What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

One mole contains about 6.02 × 10²³ molecules, so 3.01 × 10²³ molecules is 0.50 mol. At STP, 1 mol of gas occupies 22.4 L; therefore, 0.50 mol occupies 0.50 × 22.4 = 11.2 L. The correct choice is 11.2 L.

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