Question 10 • Precalculus
The graph of y = sin(x/2) − 3 has amplitude 1 and midline y = −3, so its maximum is −2 and minimum is −4. Its period is 2π ÷ (1/2) = 4π. At x = 0, the function equals −3 and is increasing, so the graph that matches is the one described in choice D.
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