How does the graph of y = sec(x – 2) + 2 compare to the graph of y = sec(x )?

In y = sec(x − 2) + 2, replacing x with x − 2 shifts the graph 2 units to the right. Adding 2 outside the secant function shifts it 2 units up. Therefore, the graph is shifted 2 units up and 2 units right, which is choice D.

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