How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?Switch the x- and y-coordinates.Use the opposites of the x- and y-coordinates.Use the reciprocals of the x- and y-coordinates.

A function and its inverse have their x- and y-coordinates reversed. So if (a, b) is a point on f⁻¹(x) = 9ˣ, then (b, a) is a point on f(x) = log₉x. Therefore, switch the x- and y-coordinates.

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