Question 10 • Precalculus
Resolve the initial velocity into horizontal and vertical components: the horizontal speed is 37 cos(70°), and the vertical speed is 37 sin(70°). Thus x(t) = 37 cos(70°)t. Since the ball starts on the ground, its initial height is 0, and gravity gives y(t) = −16t² + 37 sin(70°)t. These are the equations in choice A.
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