Question 13 • Precalculus
Move the x-term and constant to the right: y² + 6y = 12x + 39. Complete the square by adding 9 to both sides, since half of 6 is 3 and 3² = 9: (y + 3)² = 12x + 48 = 12(x + 4). So the standard form is choice B, (y + 3)² = 12(x + 4).
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