The graph of y2 + 8y – 4x – 24 = 0 is a parabola. Where is the focus located?

Complete the square in y: y² + 8y – 4x – 24 = 0 becomes (y + 4)² = 4(x + 10). Comparing with (y – k)² = 4p(x – h), the vertex is (–10, –4) and p = 1, so the focus is one unit to the right of the vertex: (–9, –4), choice A.

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