Question 1 • Precalculus
Over 5 seconds, the airplane’s horizontal position changes by 45 − 0 = 45, so its horizontal rate is 45 ÷ 5 = 9 units per second. Its vertical position changes by 160 − 10 = 150, so its vertical rate is 150 ÷ 5 = 30 units per second. Starting at (0, 10), its equations are x(t) = 9t and y(t) = 30t + 10, which is choice D.
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