AnswersFL-1200330-Algebra 2 CRGraphing Polynomial Functions

Graphing Polynomial Functions Answers

21 verified answers
3

Choose all of the zeroes of f(x).

A
–3 with multiplicity 1
B
3 with multiplicity 1
C
0 with multiplicity 1
D
0 with multiplicity 3
E
3 with multiplicity 0
5

Check all the statement(s) that are true about the polynomial function graphed.

A
Its leading coefficient is positive.
B
Its leading coefficient is negative.
C
It has an odd degree.
D
It has an even degree.
E
It has exactly two real zeroes.
F
It has exactly three real zeroes.
G
None of the zeroes have even multiplicity.
H
None of the zeroes have odd multiplicity.
7

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Blank 1:4
Blank 2:0
9

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Blank 1:1
Blank 2:2
11

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Answers:
If a zero is , then the graph of its function only touches the x–axis at that zero.:of even multiplicity
If a zero is , then the graph of its function crosses the x–axis at that zero.:of odd multiplicity
12

of odd multiplicity✔ of even multiplicity

Answers:
If a zero is , then the graph of its function only touches the x–axis at that zero.:of even multiplicity
If a zero is , then the graph of its function crosses the x–axis at that zero.:of odd multiplicity
13

✔ of odd multiplicityof even multiplicity

A
✔ of odd multiplicity
B
of even multiplicity
18

Let a and b be real numbers, where Which of the following functions could represent the graph on the right?

Question illustration
A
f(x) = x (x – a)(x – b)2
B
f(x) = (x – a)(x – b)2
C
f(x) = x(x – a)³(x – b)
D
f(x) = x2(x – a) 2(x – b)2
19

Explain how to sketch a graph of the function f(x) = x3 + 2x2 – 8x. Be sure to include end-behavior, zeroes, and intervals where the function is positive and negative.

Answer:

The function factors as f(x) = x(x + 4)(x - 2), so its zeros are -4, 0, and 2, each with multiplicity 1. Since it is an odd-degree function with a positive leading coefficient, the graph falls to the left and rises to the right. It is negative on (-∞, -4) and (0, 2), and positive on (-4, 0) and (2, ∞). The graph crosses the x-axis at each zero.

20

Did your explanation include the following?

A
The degree of the function is odd and the leading coefficient is positive – so the function goes to negative infinity as x goes to negative infinity and to positive infinity as x goes to positive infinity.
B
The zeroes are –4, 0, and 2, all with multiplicity 1.
C
The function is negative from negative infinity to –4 and from 0 to 2.
D
The function is positive from –4 to 0 and from 2 to infinity.

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