The graph of f of x is equal to the fraction with numerator 24 x squared plus 62 x plus 34 and denominator 4 x plus 3 has an oblique asymptote at y is equal to

Divide the numerator by the denominator: 24x² ÷ 4x = 6x, then subtracting 24x² + 18x leaves 44x + 34. Next, 44x ÷ 4x = 11, leaving a remainder of 1. Thus f(x) = 6x + 11 + 1/(4x + 3); the remainder term approaches 0 as x grows, so the oblique asymptote is y = 6x + 11, choice D.

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