Question 1 • Applications and Modeling
When C > 0 and r > 0, the base 1 + r is greater than 1, so y = C(1 + r)^t increases as t increases; it does not decrease from left to right. The other statements are true: setting t = 0 gives y = C, and the function matches y = ab^x when a = C and b = 1 + r. With C > 0 and r > 0, its y-values are also positive.
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