Question 11 • Foothill-B Period-Chemistry-26/27B
The original amount of nickel-59 was the nickel still present plus the cobalt-59 produced by decay: 0.17 g + 5.27 g = 5.44 g. The fraction of the original nickel that remains is 0.17 ÷ 5.44 = 1/32, which equals (1/2)^5. Therefore, 5 half-lives have passed; the correct choice is 5.
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