Select all of the ordered pairs that are solutions to the inequality:50x + 150y > 1500

Divide both sides of 50x + 150y > 1500 by 50 to get x + 3y > 30. For (1, 10), 1 + 3(10) = 31, so it satisfies the inequality; for (40, 0), 40 + 3(0) = 40, so it also satisfies it. The pair (10, 1) gives 13, which is too small, and (0, 10) gives exactly 30, which does not satisfy the strict inequality.

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